Peter Gerwinski wrote:

...

WriteLn('*',Text,'*'); { Prints out with padded #0 }

I think we agree that this is correct. (On Linux, the #0s don't appear on the screen ... I suspect the operating system (or the "terminal") "eats" them.)

Why is this correct? Isn't Text, being declared as an array of char, treated as a 0-terminated string, meaning that the #0 should not be printed? -- Frank Heckenbach, Erlangen, Germany heckenb@mi.uni-erlangen.de Turbo Pascal: http://www.mi.uni-erlangen.de/~heckenb/programs.htm Internet links: http://www.mi.uni-erlangen.de/~heckenb/links.htm