Hi If you have something like this: function foo : integer; external 'bar' name 'foo'; you get a warning that the library name in 'external' is ignored. Is it possible, instead of ignoring the library name, to generate an implicit call to link it? For example, the example above would resolve to an implicit '-lbar' (i.e., it would be the equivalent of '{$l bar}'). Is this feasible, and is there any reason why it would be a bad idea? BTW: this causes a compiler error: const barlib = 'bar'; function foo : integer; external barlib name 'foo'; Best regards, The Chief -------- Prof. Abimbola A. Olowofoyeku (The African Chief) web: http://www.greatchief.plus.com/