On 19 Jan 2017, at 19:48, Paul Isaacs paul@redpineinstruments.org wrote:
Hello,
Am I correct that, without semantic type tie-ins, that the production
new-ordinal-type = enumerated-type | subrange-type ;
is ambiguous because (a) could be both an enumerated type and the expression for the lower bound of a subrange?
Where do you see the ambiguity? enumerated-type is lexically different from subrange-type.
Bastiaan.