On Wed, Jul 19, 2006 at 10:00:28PM +0100, Martin Liddle wrote:

We have some code that compiles and runs as intended using gpc-20020502 based on gcc 2.95.2. I am now trying to get it running with gpc-20060325 based on gcc-3.4.4.

As a demonstration the program

Program Test_err; Var errno:integer; external name 'errno'; Begin Writeln(@Error number is ',Errno); End;

Compiles but fails to link with 20060325 :

"/usr/bin/ld: errno: TLS definition in /lib/libc.so.6 section .tbss mismatches non-TLS reference in /tmp/ccae8f7a.o"

The same program runs correctly with 20020522 when external name is replaced by the older syntax asmname. A bit of googling suggests this is a common problem and not limited to gpc but I can't find how I am now supposed to access errno. Any suggestions? --

I'd guess the problem is that according to the C standard, errno does not have to be a variable, it could be a macro. You may try to use a C wrapper, like this (untested):

get_errno.c:

#include <errno.h>

int get_errno (void) { return errno; }

Pascal source:

Program Test_err; {$L get_errno.c}

function errno: Cinteger; external name 'get_errno';

Begin Writeln('Error number is ',Errno); End.

Emil Jerabek