15 Feb
2010
15 Feb
'10
8:40 p.m.
I get a factor of 30 decrease in execution time while making a string out of 10,000 integers when using the following routine to append to append each new interger string to the existing string.
procedure string_append(var s,p:string);
var i,num_to_add,old_length:integer; begin old_length:=length(s); if (s.capacity-old_length<length(p)) then begin num_to_add:=s.capacity-old_length; setlength(s,s.capacity); end else begin num_to_add:=length(p); setlength(s,old_length+length(p)); end; for i:=1 to num_to_add do s[old_length+i]:=p[i]; end;
So, SetLength is all I needed.
Yours, Kevan
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Kevan Hashemi, Electrical Engineer
Physics Department, Brandeis University
http://alignment.hep.brandeis.edu/